See picture above. Because the circuit is semi-infinite, total impedance of circuit in the box is the same with total impedance of the whole circuit. So we can draw the circuit like picture below.
To make it easier, we should work with complex number.
Hence, the impedance of resistor, inductor, and capacitor are respectively

So the total impedance of the circuit is

Substitute the impedance of resistor, capacitor, and inductor at the equation above.

Solve the equation for Ztot, and we get

And now we need to change the form, so we assume that

Then give the power of two for each sides of the equation.

And now we can get


Solving these equation, and we get

So the total impedance is

Because the real part of impedance cannot be negative, so the total impedance is

So, the magnitude of total impedance is

That's my solution.
If you have any question, correction, or comment, please leave a comment below.
Thank you.

Solution - Semi-infinite RLC CircuitSocialTwist Tell-a-Friend


Anonymous said... @ March 12, 2009 at 3:40 PM

Have you recently checked your email?

P├ęter said... @ April 21, 2009 at 9:20 PM

The last row is wrong.
It is about 1.550R

Anonymous said... @ April 28, 2009 at 11:27 PM

I think you should make this clearer:
"Because the real part of impedance cannot be negative"

Anonymous said... @ July 15, 2010 at 1:55 AM

Soryy can anyone explain me how you used complex numbers in that problem.....In what type of circuit problems can we sue that

Anonymous said... @ February 20, 2012 at 1:56 PM

Good, I like these intelligent solutions.

Anonymous said... @ August 11, 2012 at 6:46 AM

can anyone please tell me..how to view the solution

Unknown said... @ October 20, 2015 at 10:47 PM

I can't see anything. All of them are picture with "sitmo" text.

TEPPY said... @ October 22, 2015 at 2:14 AM
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