Two parallel-plate capacitors, A and B, have same area, but separation of plates in capacitor B is a half of A's. The capacitors are in parallel and connected to a voltage source with emf V. Then you insert capacitor B into capacitor A, like shown below.Calculate the work done by you!
Assume capacitance of capacitor A is C and B is 2C. Ignore edge effect of capacitors.
(If you want a more challenging problem, assume the capacitor is in series, not in parallel)

Inserted CapacitorSocialTwist Tell-a-Friend


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